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math - How can I generate a set of points evenly distributed along the perimeter of an ellipse?

If I want to generate a bunch of points distributed uniformly around a circle, I can do this (python):

r = 5  #radius
n = 20 #points to generate
circlePoints = [
    (r * math.cos(theta), r * math.sin(theta))
    for theta in (math.pi*2 * i/n for i in range(n))
]

However, the same logic doesn't generate uniform points on an ellipse: points on the "ends" are more closely spaced than points on the "sides".

r1 = 5
r2 = 10
n = 20 #points to generate
ellipsePoints = [
    (r1 * math.cos(theta), r2 * math.sin(theta))
    for theta in (math.pi*2 * i/n for i in range(n))
]

Is there an easy way to generate equally spaced points around an ellipse?

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1 Answer

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by (71.8m points)

This is an old thread, but since I am seeking the same task of creating evenly spaced points along and ellipse and was not able to find an implementation, I offer this Java code that implements the pseudo code of Howard:

 package com.math;

  public class CalculatePoints {

  public static void main(String[] args) {
    // TODO Auto-generated method stub

    /*
     * 
        dp(t) = sqrt( (r1*sin(t))^2 + (r2*cos(t))^2)
        circ = sum(dp(t), t=0..2*Pi step 0.0001)

        n = 20

        nextPoint = 0
        run = 0.0
        for t=0..2*Pi step 0.0001
            if n*run/circ >= nextPoint then
                set point (r1*cos(t), r2*sin(t))
                nextPoint = nextPoint + 1
            next
            run = run + dp(t)
        next
     */


    double r1 = 20.0;
    double r2 = 10.0;

    double theta = 0.0;
    double twoPi = Math.PI*2.0;
    double deltaTheta = 0.0001;
    double numIntegrals = Math.round(twoPi/deltaTheta);
    double circ=0.0;
    double dpt=0.0;

    /* integrate over the elipse to get the circumference */
    for( int i=0; i < numIntegrals; i++ ) {
        theta += i*deltaTheta;
        dpt = computeDpt( r1, r2, theta);
        circ += dpt;
    }
    System.out.println( "circumference = " + circ );

    int n=20;
    int nextPoint = 0;
    double run = 0.0;
    theta = 0.0;

    for( int i=0; i < numIntegrals; i++ ) {
        theta += deltaTheta;
        double subIntegral = n*run/circ;
        if( (int) subIntegral >= nextPoint ) {
            double x = r1 * Math.cos(theta);
            double y = r2 * Math.sin(theta);
            System.out.println( "x=" + Math.round(x) + ", y=" + Math.round(y));
            nextPoint++;
        }
        run += computeDpt(r1, r2, theta);
    }
}

static double computeDpt( double r1, double r2, double theta ) {
    double dp=0.0;

    double dpt_sin = Math.pow(r1*Math.sin(theta), 2.0);
    double dpt_cos = Math.pow( r2*Math.cos(theta), 2.0);
    dp = Math.sqrt(dpt_sin + dpt_cos);

    return dp;
}

}

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