Welcome toVigges Developer Community-Open, Learning,Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
737 views
in Technique[技术] by (71.8m points)

scope - Why does this function return a different value every time?

Can someone explain the following behavior? Specifically, why does the function return a different list every time? Why isn't some-list initialized to '(0 0 0) every time the function is called?

(defun foo ()
  (let ((some-list '(0 0 0)))
    (incf (car some-list))
    some-list))

Output:

> (foo)
(1 0 0)
> (foo)
(2 0 0)
> (foo)
(3 0 0)
> (foo)
(4 0 0)

Thanks!

EDIT:

Also, what is the recommended way of implementing this function, assuming I want the function to output '(1 0 0) every time?

Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

'(0 0 0) is a literal object, which is assumed to be a constant (albeit not protected from modification). So you're effectively modifying the same object every time. To create different objects at each function call use (list 0 0 0).

So unless you know, what you're doing, you should always use literal lists (like '(0 0 0)) only as constants.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to Vigges Developer Community for programmer and developer-Open, Learning and Share

2.1m questions

2.1m answers

63 comments

56.7k users

...