Check if the array is descending up to the local minimum and then ascending after it in C

Question

**My task is: The user should input numbers until -1 is pressed. The array consisting of those elements should be formed. I need to check is the array is descending up to the local minimum and ascending after it. If this condition is satisfied 'Yes' should be printed, 'No' in the opposite case. I don't know what is wrong with my code, so I hope you could help. I am beginner.

int main() {
    int a[100],n=0,b,i,j=0,c=0,h;
    for (i=0;i<100;i++){
        if (b==-1)
            break;
        else {scanf("%d", &b);
            a[i]=b;
            n++;
        }
    }
    if (n<3)
        printf("Not enough elements");

    else{
        for (i=0;i<n;i++){
            for(j=0;j<n;j++)
                a[j]=a[i];
        }
        for (i=0;i<n;i++){
            if (a[i]>a[i+1] && i!=n-1)
                continue;
            else if (a[i]<a[i+1]){
                c=1;
                h=i;
                break;
            }
        }    


        if (c==1 && h==i){
            for(j=i;j<n;i++){
                if(a[j]<a[j+1])
                    continue;
                else if(a[j]>a[j+1] || a[j+1]==a[j]){
                    break;
                    c=0;
                }

            }
            if(j==n-1 && c==1)
                printf("Yes");
            else if (c==0)
                printf("No");   
        }

    }


}

Answer 1

This code can help you :

#include <stdio.h>

int main() {
    int a[100],n=0,b,i,j=0,c=0,h;
    do
    {
        printf("Give me a number :");
        scanf("%d", &b);
        a[j]=b;
        j++;
    }while(b!=-1);
    i=0;
    j--;
    if (j<3)
    {
        printf("Not enough elements");
    }
    else
    {
        i=0;
        while(i<j-1 && a[i]>a[i+1])
        {
            i++;
        }
        if(i==j-1)
        {
            printf("No");
            return 0;
        }
        else
        {
            c=i;
            while(a[c+1]>a[c]&&c<j-1)
            {
                c++;
            }
        }
    }
    if(c==j-1)
    {
        printf("Yes");
    }
    else
    {
        printf("No");
    }
}