Welcome toVigges Developer Community-Open, Learning,Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.4k views
in Technique[技术] by (71.8m points)

flutter - How to get height of a Widget?

I don't understand how LayoutBuilder is used to get the height of a Widget.

I need to display the list of Widgets and get their height so I can compute some special scroll effects. I am developing a package and other developers provide widget (I don't control them). I read that LayoutBuilder can be used to get height.

In very simple case, I tried to wrap Widget in LayoutBuilder.builder and put it in the Stack, but I always get minHeight 0.0, and maxHeight INFINITY. Am I misusing the LayoutBuilder?

EDIT: It seems that LayoutBuilder is a no go. I found the CustomSingleChildLayout which is almost a solution.

I extended that delegate, and I was able to get the height of widget in getPositionForChild(Size size, Size childSize) method. BUT, the first method that is called is Size getSize(BoxConstraints constraints) and as constraints, I get 0 to INFINITY because I'm laying these CustomSingleChildLayouts in a ListView.

My problem is that SingleChildLayoutDelegate getSize operates like it needs to return the height of a view. I don't know the height of a child at that moment. I can only return constraints.smallest (which is 0, the height is 0), or constraints.biggest which is infinity and crashes the app.

In the docs it even says:

...but the size of the parent cannot depend on the size of the child.

And that's a weird limitation.

Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

To get the size/position of a widget on screen, you can use GlobalKey to get its BuildContext to then find the RenderBox of that specific widget, which will contain its global position and rendered size.

Just one thing to be careful of: That context may not exist if the widget is not rendered. Which can cause a problem with ListView as widgets are rendered only if they are potentially visible.

Another problem is that you can't get a widget's RenderBox during build call as the widget hasn't been rendered yet.


But I need to the size during the build! What can I do?

There's one cool widget that can help: Overlay and its OverlayEntry. They are used to display widgets on top of everything else (similar to stack).

But the coolest thing is that they are on a different build flow; they are built after regular widgets.

That have one super cool implication: OverlayEntry can have a size that depends on widgets of the actual widget tree.


Okay. But don't OverlayEntry requires to be rebuilt manually?

Yes, they do. But there's another thing to be aware of: ScrollController, passed to a Scrollable, is a listenable similar to AnimationController.

Which means you could combine an AnimatedBuilder with a ScrollController, it would have the lovely effect to rebuild your widget automatically on a scroll. Perfect for this situation, right?


Combining everything into an example:

In the following example, you'll see an overlay that follows a widget inside ListView and shares the same height.

import 'package:flutter/material.dart';
import 'package:flutter/scheduler.dart';

class MyHomePage extends StatefulWidget {
  const MyHomePage({Key key, this.title}) : super(key: key);
  final String title;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
  final controller = ScrollController();
  OverlayEntry sticky;
  GlobalKey stickyKey = GlobalKey();

  @override
  void initState() {
    if (sticky != null) {
      sticky.remove();
    }
    sticky = OverlayEntry(
      builder: (context) => stickyBuilder(context),
    );

    SchedulerBinding.instance.addPostFrameCallback((_) {
      Overlay.of(context).insert(sticky);
    });

    super.initState();
  }

  @override
  void dispose() {
    sticky.remove();
    super.dispose();
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: ListView.builder(
        controller: controller,
        itemBuilder: (context, index) {
          if (index == 6) {
            return Container(
              key: stickyKey,
              height: 100.0,
              color: Colors.green,
              child: const Text("I'm fat"),
            );
          }
          return ListTile(
            title: Text(
              'Hello $index',
              style: const TextStyle(color: Colors.white),
            ),
          );
        },
      ),
    );
  }

  Widget stickyBuilder(BuildContext context) {
    return AnimatedBuilder(
      animation: controller,
      builder: (_,Widget child) {
        final keyContext = stickyKey.currentContext;
        if (keyContext != null) {
          // widget is visible
          final box = keyContext.findRenderObject() as RenderBox;
          final pos = box.localToGlobal(Offset.zero);
          return Positioned(
            top: pos.dy + box.size.height,
            left: 50.0,
            right: 50.0,
            height: box.size.height,
            child: Material(
              child: Container(
                alignment: Alignment.center,
                color: Colors.purple,
                child: const Text("^ Nah I think you're okay"),
              ),
            ),
          );
        }
        return Container();
      },
    );
  }
}

Note:

When navigating to a different screen, call following otherwise sticky would stay visible.

sticky.remove();

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to Vigges Developer Community for programmer and developer-Open, Learning and Share
...